/*
The smallest number m such that 10 divides m! is m=5.
The smallest number m such that 25 divides m! is m=10.

Let s(n) be the smallest number m such that n divides m!.
So s(10)=5 and s(25)=10.
Let S(n) be ∑s(i) for 2 ≤ i ≤ n.
S(100)=2012.


Find S(108).

Anser:
Time:
*/
package main

import (
	"fmt"
	"time"
)

func main() {
	tstart := time.Now()



	tend := time.Now()
	fmt.Println(tend.Sub(tstart))
}